两个线程循环输出1-100，一个输出奇数，一个输出偶数
可以用Condition去实现这个功能。开启两个线程去获取同一个可重入锁.获取到锁之后打印当前的值，再使用condition.signal()唤醒另一个线程，然后自己condition.await()。最后释放锁。两个线程使用同样的代码。每次只有一个线程运行进行来实现交替输出
直接上代码
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| import org.jooq.lambda.Unchecked;
import org.junit.jupiter.api.Assertions;
import org.junit.jupiter.api.RepeatedTest;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.atomic.AtomicInteger;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.ReentrantLock;
public class ConcurrentTest {
@RepeatedTest(1000)
void eachExc() throws Exception {
ReentrantLock lock = new ReentrantLock();
Condition condition = lock.newCondition();
CountDownLatch countDownLatch = new CountDownLatch(2);
AtomicInteger count = new AtomicInteger(1);
List<Integer> resultA = new ArrayList<>();
List<Integer> resultB = new ArrayList<>();
new Thread(Unchecked.runnable(() -> {
while (true) {
lock.lock();
try {
if (count.get() > 100) {
countDownLatch.countDown();
condition.signal();
return;
}
int value = count.getAndIncrement();
resultA.add(value);
condition.signal();
condition.await();
} finally {
lock.unlock();
}
}
}), "A").start();
new Thread(Unchecked.runnable(() -> {
while (true) {
lock.lock();
try {
if (count.get() > 100) {
countDownLatch.countDown();
condition.signal();
return;
}
int value = count.getAndIncrement();
resultB.add(value);
condition.signal();
condition.await();
} finally {
lock.unlock();
}
}
}), "B").start();
countDownLatch.await();
System.out.println(resultA);
System.out.println(resultB);
// 校验结果是否正确
Assertions.assertEquals(resultA.size(), 50);
Assertions.assertEquals(resultB.size(), 50);
boolean isAOdd = resultA.get(0) % 2 != 0;
Assertions.assertAll(() -> {
for (Integer integer : resultA) {
boolean isOdd = integer % 2 != 0;
if(isAOdd && !isOdd){
throw new IllegalArgumentException("A");
}
}
for (Integer integer : resultB) {
boolean isOdd = integer % 2 != 0;
if(isAOdd && isOdd){
throw new IllegalArgumentException("B");
}
}
});
}
}
|